F(x)=7(x^2+20)

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Solution for F(x)=7(x^2+20) equation: 



(F)=7(F^2+20)

We move all terms to the left:

(F)-(7(F^2+20))=0



We calculate terms in parentheses: -(7(F^2+20)), so:

7(F^2+20)

We multiply parentheses

7F^2+140

Back to the equation:

-(7F^2+140)



We get rid of parentheses

-7F^2+F-140=0

a = -7; b = 1; c = -140;
Δ = b2-4ac
Δ = 12-4·(-7)·(-140)
Δ = -3919
Delta is less than zero, so there is no solution for the equation

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